\(\int \frac {x^4}{(c+a^2 c x^2)^{5/2} \arctan (a x)} \, dx\) [515]

Optimal result

Integrand size = 24, antiderivative size = 24 \[ \int \frac {x^4}{\left (c+a^2 c x^2\right )^{5/2} \arctan (a x)} \, dx=\text {Int}\left (\frac {x^4}{\left (c+a^2 c x^2\right )^{5/2} \arctan (a x)},x\right ) \]

[Out]

Unintegrable(x^4/(a^2*c*x^2+c)^(5/2)/arctan(a*x),x)

Rubi [N/A]

Not integrable

Time = 0.09 (sec) , antiderivative size = 24, normalized size of antiderivative = 1.00, number of steps used = 0, number of rules used = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \[ \int \frac {x^4}{\left (c+a^2 c x^2\right )^{5/2} \arctan (a x)} \, dx=\int \frac {x^4}{\left (c+a^2 c x^2\right )^{5/2} \arctan (a x)} \, dx \]

[In]

Int[x^4/((c + a^2*c*x^2)^(5/2)*ArcTan[a*x]),x]

[Out]

Defer[Int][x^4/((c + a^2*c*x^2)^(5/2)*ArcTan[a*x]), x]

Rubi steps \begin{align*} \text {integral}& = \int \frac {x^4}{\left (c+a^2 c x^2\right )^{5/2} \arctan (a x)} \, dx \\ \end{align*}

Mathematica [F(-1)]

Timed out. \[ \int \frac {x^4}{\left (c+a^2 c x^2\right )^{5/2} \arctan (a x)} \, dx=\text {\$Aborted} \]

[In]

Integrate[x^4/((c + a^2*c*x^2)^(5/2)*ArcTan[a*x]),x]

[Out]

$Aborted

Maple [N/A] (verified)

Not integrable

Time = 12.28 (sec) , antiderivative size = 22, normalized size of antiderivative = 0.92

\[\int \frac {x^{4}}{\left (a^{2} c \,x^{2}+c \right )^{\frac {5}{2}} \arctan \left (a x \right )}d x\]

[In]

int(x^4/(a^2*c*x^2+c)^(5/2)/arctan(a*x),x)

[Out]

int(x^4/(a^2*c*x^2+c)^(5/2)/arctan(a*x),x)

Fricas [N/A]

Not integrable

Time = 0.24 (sec) , antiderivative size = 62, normalized size of antiderivative = 2.58 \[ \int \frac {x^4}{\left (c+a^2 c x^2\right )^{5/2} \arctan (a x)} \, dx=\int { \frac {x^{4}}{{\left (a^{2} c x^{2} + c\right )}^{\frac {5}{2}} \arctan \left (a x\right )} \,d x } \]

[In]

integrate(x^4/(a^2*c*x^2+c)^(5/2)/arctan(a*x),x, algorithm="fricas")

[Out]

integral(sqrt(a^2*c*x^2 + c)*x^4/((a^6*c^3*x^6 + 3*a^4*c^3*x^4 + 3*a^2*c^3*x^2 + c^3)*arctan(a*x)), x)

Sympy [N/A]

Not integrable

Time = 5.59 (sec) , antiderivative size = 22, normalized size of antiderivative = 0.92 \[ \int \frac {x^4}{\left (c+a^2 c x^2\right )^{5/2} \arctan (a x)} \, dx=\int \frac {x^{4}}{\left (c \left (a^{2} x^{2} + 1\right )\right )^{\frac {5}{2}} \operatorname {atan}{\left (a x \right )}}\, dx \]

[In]

integrate(x**4/(a**2*c*x**2+c)**(5/2)/atan(a*x),x)

[Out]

Integral(x**4/((c*(a**2*x**2 + 1))**(5/2)*atan(a*x)), x)

Maxima [N/A]

Not integrable

Time = 0.35 (sec) , antiderivative size = 24, normalized size of antiderivative = 1.00 \[ \int \frac {x^4}{\left (c+a^2 c x^2\right )^{5/2} \arctan (a x)} \, dx=\int { \frac {x^{4}}{{\left (a^{2} c x^{2} + c\right )}^{\frac {5}{2}} \arctan \left (a x\right )} \,d x } \]

[In]

integrate(x^4/(a^2*c*x^2+c)^(5/2)/arctan(a*x),x, algorithm="maxima")

[Out]

integrate(x^4/((a^2*c*x^2 + c)^(5/2)*arctan(a*x)), x)

Giac [N/A]

Not integrable

Time = 75.96 (sec) , antiderivative size = 3, normalized size of antiderivative = 0.12 \[ \int \frac {x^4}{\left (c+a^2 c x^2\right )^{5/2} \arctan (a x)} \, dx=\int { \frac {x^{4}}{{\left (a^{2} c x^{2} + c\right )}^{\frac {5}{2}} \arctan \left (a x\right )} \,d x } \]

[In]

integrate(x^4/(a^2*c*x^2+c)^(5/2)/arctan(a*x),x, algorithm="giac")

[Out]

sage0*x

Mupad [N/A]

Not integrable

Time = 0.42 (sec) , antiderivative size = 24, normalized size of antiderivative = 1.00 \[ \int \frac {x^4}{\left (c+a^2 c x^2\right )^{5/2} \arctan (a x)} \, dx=\int \frac {x^4}{\mathrm {atan}\left (a\,x\right )\,{\left (c\,a^2\,x^2+c\right )}^{5/2}} \,d x \]

[In]

int(x^4/(atan(a*x)*(c + a^2*c*x^2)^(5/2)),x)

[Out]

int(x^4/(atan(a*x)*(c + a^2*c*x^2)^(5/2)), x)